Chemistry - Thermodynamics - 1 Question with Solution | TestHub

ChemistryThermodynamics - 1Adiabatic Process/PolytropicEasy2 minPYQ_2020

ChemistryEasynumerical

Two moles of a gas at 8.21 bar and 300 K are expanded at constant temperature up to 2.73 bar against a constant pressure of 1 bar. How much work (in Latm) is done by the gas?

(neglect the sign)

Answer:

12.00

Solution:

$V_{1} = \frac{2 \times 0.0821 \times 300}{8.21} = 6.0 L$

$V_{2} = \frac{2 \times 0.0821 \times 300}{2.73} = 18.0 L$

$W_{i r r, i s o t h e r m a l} = - P_{e x t} \times Δ V = - 1 \times (18 - 6)$

$= - 12 L a t m$

Stream:NTA_ABHYASSubject:ChemistryTopic:Thermodynamics - 1Subtopic:Adiabatic Process/Polytropic

⏱ 2mℹ️ Source: PYQ_2020

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