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ChemistryThermochemistryEnthalpy of NeutralisationEasy2 minQB
ChemistryEasysingle choice

When 1 g-equivalent of a strong acid reacts with a strong base, 13.7 kcal of heat is released. When 1 g-equivalent of the weak acid HA is neutralized by a strong base, 12.7 kcal is released. When 1 g-equivalent of the weak base BOH is neutralized by a strong acid, 12.2 kcal is released. What is the enthalpy change when 1 mole of HA is completely neutralized by BOH?

Options:

Answer:
A
Solution:

The enthalpy of ionization for HA is calculated as the difference between the final and initial states: -12.7 - (-13.7) = +1.0 kcal/eq.

 

Similarly, for BOH, the enthalpy of ionization is: -12.2 - (-13.7) = +1.5 kcal/eq.

 

The total enthalpy of neutralization for HA by BOH per equivalent is the sum of the standard neutralization enthalpy and the ionization enthalpies: -13.7 + 1.0 + 1.5 = -11.2 kcal.

 

Since HA is a monobasic acid, 1 mole is equal to 1 equivalent. Therefore, the enthalpy change (ΔH) for the reaction is -11.2 kcal. This corresponds to option (a).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Neutralisation
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