The combustion of benzene (L) gives CO 2 ( g ) and H 2 O ( L ) . Given that heat of combustion of benzene at constant volume is − 3263.9 kJ mol − 1 at 2 5 ∘ C ; heat of combustion (in kJ mol − 1 )

Question

The combustion of benzene (L) gives CO 2 ​ ( g ) and H 2 ​ O ( L ) . Given that heat of combustion of benzene at constant volume is − 3263.9 kJ mol − 1 at 2 5 ∘ C ; heat of combustion (in kJ mol − 1 ) of benzene at constant pressure will be : ( R = 8.314 JK − 1 mol − 1 )

TestHub · Accepted Answer

C 6 ​ H 6 ​ ( I ) + 2 15 ​ O 2 ​ ( g ) → 6 CO 2 ​ ( g ) + 3 H 2 ​ O ( l ) Δ n g ​ = 6 − 2 15 ​ = − 2 3 ​ Δ H = Δ U + Δ n g ​ RT = − 3263.9 + ( − 2 3 ​ ) × 8.314 × 1 0 − 3 × 298 = − 3263.9 + ( − 3.71 ) = − 3267.6 kJ mol − 1

Chemistry - Thermochemistry Question with Solution | TestHub

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