Chemistry - Thermochemistry Question with Solution | TestHub

The enthalpies of neutralization of a weak acid $\mathrm{HA}\&$ a weak acid HB by NaOH are $-6900\mathrm{Cal}/$ equivalent $\&-2900\mathrm{Cal}/$ equivalent respectively. When one equivalent of NaOH is added to a solution containing one equivalent of HA \& one equivalent of HB , the enthalpy change was -3900 Calories. If base distributed between $\mathrm{HA}\&\mathrm{HB}$ in $\mathrm{X}:\mathrm{Y}$ (simplest ratio) then find value of $\mathrm{X}+\mathrm{Y}$.