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ChemistryThermochemistryEnthalpy of CombustionMedium2 minQB

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The enthalpies of combustion of C_(graphite) and C_(diamond)are −393.5 and −395.4 kJ/mol respectively. The enthalpy of conversion of C_(graphite)to C_(diamond) in kJ/mol is

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Answer:

Solution:

C $_{g r a p hi t e}$ + O₂ ⟶ CO₂ ; $Δ H = - 393.5$

C $_{d iam o n d}$ + O₂ ⟶ CO₂ ; $Δ H = - 395.4$

Therefore, C $_{g r a p hi t e}$ ⟶ C $_{d iam o n d}$ $= - 393.5 + 395.4 = 1.9$

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion

⏱ 2mℹ️ Source: QB

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