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ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2021
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When 400 mL of 0.2 M H2SO4 solution is mixed with 600 mL of 0.1MNaOH solution, the increase in temperature of the final solution is ×10-2 K. (Round off to the nearest integer).

[Use :H+(aq)+OH-(aq)H2O:ΔγH=-57.1 kJ mol-1 

Specific heat of H2O=4.18 J K-1 g-1 , density of H2O=1.0 g cm-3 

Assume no change in volume of solution on mixing.

Answer:
82
Solution:

nH+=400×0.21000×2=0.16

nOH-=600×0.11000=0.06( Limiting Reagent)

Now we can apply, q=msT

 0.06×57.1×103

=(1000×1.0)×4.18×ΔT

ΔT=0.8196 K

=81.96×10-2 K82×10-2 K

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
2mℹ️ Source: PYQ_2021

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