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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the mixture is well shaken. This rise in temperature $T_{1}$ is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature $T_{2}$ is again noted. Which of the following is correct?

Options:

Answer:

Solution:

Heat produced by 200 Meq. of KOH + HCl
$= \frac{13.7 \times 200}{1000} k c a l$
This is used to raise the temperature of 400 mL. Solution say $T_{1}$
Thus, $\frac{13.7 \times 200}{1000} = 400 \times S \times T_{1}$
Now, heat produced by 100 Meq of KOH + HCl
$= \frac{13.7 \times 100}{1000}$
Thus, $- \frac{13.7 \times 100}{1000} = 200 \times S \times T_{2}$
It is evident that $T_{1} = T_{2}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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