Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of CombustionMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
Study the following thermochemical equations:
2CO(g) + O2(g) → 2CO2(g); ΔH = -566 kJ
CO(g) + N2O(g) → CO2(g) + N2(g); ΔH = -366 kJ
CO(g) + NO2(g) → CO2(g) + NO(g); ΔH = -226 kJ
(Relative atomic masses: C = 12, N = 14, O = 16)
Which oxidizing agent will generate the greatest amount of energy for 1 mole of CO(g)?
Options:
Answer:
B
Solution:
Energy per mol CO: with O2, 566/2 = 283 kJ; with N2O, 366 kJ; with NO2, 226 kJ. The greatest is with N2O. Ans (b).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB
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