Chemistry - Thermochemistry Question with Solution | TestHub

Enthalpy of neutralisation is the amount of energy released during the combination of one moe strong monobasic acid neutralised with the one-mole strong monoacidic base.

${\mathrm{H}}^{+}\left(\mathrm{aq}\right) + {\mathrm{OH}}^{-}\left(\mathrm{aq}\right)\to {\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right) {∆}_{\mathrm{neut}.}\mathrm{H} =-13.7 \mathrm{kcal}$

Enthalpy of ionisation of ${\mathrm{CH}}_3\mathrm{COOH}$ & ${\mathrm{NH}}_4\mathrm{OH}$ together

$=-\text{10.5}-\left(-\text{13.7}\right)=+\text{3.2 Kcal}$

Enthalpy of ionisation of only ${\mathrm{NH}}_4\mathrm{OH}$

$=-\text{11.7}-\left(-\text{13.7}\right)=+\text{2 Kcal}$

Enthalpy of ionisation of only ${\mathrm{CH}}_3\mathrm{COOH}$

$=\text{3.2}-\text{2}=1.\text{2 Kcal}$