Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryBorn Haber CycleMedium2 minQB
ChemistryMediumnumerical
Calculate ΔHvap [CH3COOH(l)] in kJ/mol from the following data: ΔHSolution [CsF·CH3COOH(s)] in glacial acetic acid = -5 kJ/mol; ΔHSolution [CsF(s)] in glacial acetic acid = +33 kJ/mol; the strength of H-bond between F-(g) and CH3COOH(g) = +50 kJ/mol; lattice enthalpy of CsF·CH3COOH(s) = +740 kJ/mol; lattice enthalpy of CsF(s) = +801 kJ/mol.
Answer:
27.00
Solution:
Let CsF(s) + CH3COOH(l) → CsF·CH3COOH(s) have ΔH1. Both solids give the same solution: ΔH1 + (-5) = 33, so ΔH1 = +38 kJ. Cycle: ΔH1 + 740 = 801 + ΔHvap - 50, so 778 = 751 + ΔHvap and ΔHvap = 27 kJ/mol. The answer is 0027.
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Born Haber Cycle
⏱ 2mℹ️ Source: QB
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