Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2023
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The enthalpy change for the conversion of12Cl2(g) toCl-(aq)is(-)
kJmol-1(Nearest integer)
Given :Δdis HCl2( g)0=240kJmol-1.
ΔegHCl(g)o=-350kJmol-1,
ΔhydHCl(g)-o=-380kJmol-1

Answer:
610
Solution:

12Cl2( g) → Cl(g) → Cl(g)- → Cl(aq.)-

Apply Hess's law,

∆H = 12 ∆dis HCl2 (g)0 + ∆egHCl(g)o + ∆hydHCl(g)-o

⇒ ∆H=12× 240 + (-350) + (-380)

⇒ ∆H = -610

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: PYQ_2023

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