Chemistry - Thermochemistry Question with Solution | TestHub

Given : Weight of benzoic acid $=1.89\mathrm{g}$; Temperature of bomb calorimeter $=25^{\circ }\mathrm{C}=298\mathrm{K}$; Mass of water $(m)=18.94\mathrm{kg}=18940\mathrm{g}$; Increase in temperature $(\Delta t)=0.632^{\circ }\mathrm{C}$ and specific heat of water $(s)=0.998\mathrm{cal}/\mathrm{g}$-deg. We know that heat gained by water or heat liberated by benzoic acid $(Q)=ms\Delta t$ $=\frac{11946.14\times 122}{1.89}=771126.5\mathrm{cal}=771.12\mathrm{kcal}$