Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of NeutralisationHard2 minQB
ChemistryHardnumerical
The enthalpies of neutralization of a weak acid HA and a weak acid HB by NaOH are -7800 cal/equivalent and -3900 cal/equivalent, respectively. When one equivalent of NaOH is added to a solution containing one equivalent of HA and one equivalent of HB, the enthalpy change was -5200 cal. If the base is distributed between HA and HB in the ratio 1 : x, the value of 'x' is
Answer:
2.00
Solution:
Of 1 equivalent of NaOH, 1/1+x goes to HA and x/1+x to HB: 7800/1+x + 3900x/1+x = 5200. So 7800 + 3900x = 5200 + 5200x, giving x = 2. Answer: 2.
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Neutralisation
⏱ 2mℹ️ Source: QB
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