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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

The bond dissociation energies of $X_{2}, Y_{2}$ and XY are in the ratio of 1 : 0.5 : 1. $Δ H$ for the formation of XY is –200 kJ $m o l^{- 1}$ . The bond dissociation energy of $X_{2}$ will be

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Solution:

he reaction for $Δ_{f} H ° (X Y)$
$\frac{1}{2} X_{2} (g) + \frac{1}{2} Y_{2} (g) \to X Y (g)$
Bond energies of $X_{2}, Y_{2}$ and XY are $X, \frac{X}{2}$ and X respectively.
Hence $Δ H = (\frac{X}{2} + \frac{X}{4}) - X = - 200$
On solving, we get $- \frac{X}{2} + \frac{X}{4} = - 200$
$X = 800 k J / m o l e$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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