Chemistry - Thermochemistry Question with Solution | TestHub
When 1 g-equivalent of strong acid reacts with strong base, heat released is 13.5 kcal. When 1 g-equivalent H2A is completely neutralized against strong base, 13 kcal is released. When 1 g-equivalent B(OH)2 is completely neutralized against strong acid, 10 kcal heat is released. What is the enthalpy change when 1 mole of H2A is completely neutralized by B(OH)2?
Options:
Answer:
Solution:
The enthalpy of ionization for H₂A is calculated as:
-13 - (-13.5) = +0.5 kcal/eq
For B(OH)₂, the enthalpy of ionization is:
-10 - (-13.5) = +3.5 kcal/eq
The neutralization of H₂A by B(OH)₂ per equivalent is:
-13.5 + 0.5 + 3.5 = -9.5 kcal/eq
Since one mole of H₂A contains 2 equivalents, the total enthalpy change (Δ H) is:
Δ H = 2 × (-9.5) = -19 kcal
This corresponds to option (d).
