Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryMiscelleneous EnthalpiesHard2 minQB
ChemistryHardmatching list
Match the columns
Column I | Column II |
|---|---|
P) C (graphite) + O2(g) → CO2(g) | i) ΔHformation |
Q) C (graphite) → C(g) | ii) ΔHcombustion |
R) HCl(aq) + OH-(aq) → Cl-(aq) + H2O(l) | iii) ΔHatomization |
| iv) ΔHneutralization |
(Column I = Reaction; Column II = Δr H is also known as)
Options:
Answer:
B
Solution:
P: Burning graphite to CO₂ is both the combustion of carbon and the standard formation of CO₂, so P corresponds to (i) and (ii).
Q: Converting graphite to gaseous atomic carbon is the atomization (sublimation) of carbon and also the standard formation of C(g), so Q corresponds to (i) and (iii).
R: A strong acid neutralizing OH⁻ to water is a neutralization reaction, so R corresponds to (iv).
Therefore, the correct matches are P-(i, ii), Q-(i, iii), and R-(iv).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Miscelleneous Enthalpies
⏱ 2mℹ️ Source: QB
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