Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of ReactionEasy2 minQB
ChemistryEasysingle choice
Passage / Comprehension
For the reaction at 25°C, Y2O4(l) → 2YO2(g), Δ E° = 2.1 kcal and ΔS° = 8 cal/K.
ΔG° for the reaction is
Options:
Answer:
B
Solution:
Δng = 2 - 0 = 2. ΔH = Δ E + Δng RT = 2100 + 2(2)(298) = 3292 cal (R = 2 cal/K-mol). ΔG = ΔH - TΔS = 3292 - 298(8) = 3292 - 2384 = +908 cal ≈ +0.91 kcal. This is option (b).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: QB
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