Chemistry - Thermochemistry Question with Solution | TestHub
An intimate mixture of hydrogen gas and the theoretical amount of air at 25°C and a total pressure of 1 atm, is exposed in a closed rigid vessel. If the process occurs under adiabatic condition, then using the following data, answer the following questions:
Given: (i) CP,m = 8.3 cal/K-mol (ii) CP,m = 11.3 cal/K-mol (iii) Δf H [H2O(g)] = -57.8 kcal (iv) Air contains 20% O2 and 80% N2 by volume
If at initial temperature, T1, E1 is the internal energy and at higher temperature T2, E2 is the internal energy, then
Options:
Answer:
Solution:
The vessel is rigid, meaning work (w) is 0, and adiabatic, meaning heat (q) is 0. Therefore, the change in internal energy, Δ U = q + w = 0. This implies that the chemical energy lost is equal to the thermal energy gained, so E1 = E2. This corresponds to option (c).
