Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of solution/dilution/hydrationEasy2 minQB
ChemistryEasysingle choice

As a 0.2 mole sample of solid KNO3 was dissolved in 100 ml of water, the temperature of the solution decreased. A small electrical immersion heater restored the temperature of the system by passing 0.25 A from a 12 V power supply for 10 min. ΔH for the process: KNO3(s) → KNO3(aq) is

Options:

Answer:
C
Solution:

Electrical energy = VIt = 12 × 0.25 × 600 = 1800 J, equal to the heat absorbed by 0.2 mol. Per mole: 1800/0.2 = 9000 J = 9.0 kJ/mol. The solution cooled (endothermic): ΔH = +9.0 kJ/mol. This is option (c).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of solution/dilution/hydration
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