Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of CombustionEasy2 minQB
ChemistryEasysingle choice
Passage / Comprehension
When 24 g of carbon reacted with oxygen to form CO and CO2 at 298 K and constant pressure, 133.6 kcal of heat was liberated and no carbon remained. Heat of formation of CO and CO2 are -26.0 and -94.0 kcal/mole, respectively.
Moles of CO formed is
Options:
Answer:
B
Solution:
24 g C = 2 mol. Let CO = x and CO2 = 2 - x. Heat = 26x + 94(2-x) = 188 - 68x = 133.6, so x = 54.4/68 = 0.8 mol. This is option (b).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB
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