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ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2022
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17.0 gofNH3completely vapourises at-33.42 °Cand1bar pressure and the enthalpy change in the process is23.4 kJ mol-1. The enthalpy change for the vapourisation of85 gofNH3under the same conditions iskJ.

Answer:
117
Solution:

17.0 g of NH3 = 1717 = 1 mole and the enthalpy change = 23.4 kJ mol-1.

 85 g of NH3 = 8517 = 5 moles enthalpy change under the same conditions will be = 23.4×5=117 kJ.

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
2mℹ️ Source: PYQ_2022

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