If the standard molar enthalpy change for combustion of graphite powder is $- 2.48 \times 10^{2} kJ {mol}^{- 1}$ , the amount of heat generated on combustion of $1 g$ of graphite powder in $kJ$ (Nearest integer):
Answer:
21
Solution:
$1 mol$ graphite $= 12 gmC$
Ans. $= \frac{248}{12} = 20.67 kJ / gm$ heat evolved

Question

If the standard molar enthalpy change for combustion of graphite powder is - 2 . 48 × 10 2 kJ mol - 1 , the amount of heat generated on combustion of 1 g of graphite powder in kJ (Nearest integer):

TestHub · Accepted Answer

1 mol graphite = 12 gmC Ans. = 248 12 = 20 . 67 kJ / gm heat evolved

Chemistry - Thermochemistry Question with Solution | TestHub

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