Chemistry - Thermochemistry Question with Solution | TestHub

As 6020 J is required to melt 18 g of ice at 0oC
So, 1 J would melt$=\frac{18}{6020}\mathrm{g}$of ice at${0\mathrm{}}^{\mathrm{o}}\mathrm{C}$$\approx 3\times 10^{-3}\mathrm{g}$
Hence 500 J would melt$=500\times 3\times 10^{-3}$g of ice at${0\mathrm{}}^{\mathrm{o}}\mathrm{C}$$=$1.5 g