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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2019

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The difference between $∆ H$ and $∆ U$ is $(∆ H - ∆ U)$ , when the combustion of one mole of heptane $(l)$ is carried out at a temperature $T$ , is equal to:

Options:

Answer:

Solution:

Combustion of heptane

$C_{7} H_{16} (l) + 11 O_{2} (g) ⟶ 7 C O_{2} (g) + 8 H_{2} O (l)$

$∆ H = ∆ U + ∆ n g R T$

$∆ H - ∆ U = ∆ n g R T$

$∴ ∆ n g = 7 - 11 = - 4$

$= - 4 \times R T$

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2019

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