Chemistry - Thermochemistry Question with Solution | TestHub

Isobutane and n-butane$\left[{\mathrm{C}}_4{\mathrm{H}}_{10}\right]$have same molecular formula;${\mathrm{C}}_4{\mathrm{H}}_{10}+\frac{13}{2}{\mathrm{O}}_2\to 4\mathrm{C}{\mathrm{O}}_2+5{\mathrm{H}}_2\mathrm{O}$
For$58$$\mathrm{g}\mathrm{m}$of${\mathrm{C}}_4{\mathrm{H}}_{10}$$208\mathrm{g}\mathrm{m}$${\mathrm{O}}_2$is required then for$5\mathrm{k}\mathrm{g}$of${\mathrm{C}}_4{\mathrm{H}}_{10}$${\mathrm{O}}_2=\frac{5\times 208}{58}=\mathrm{17.9 }\mathrm{}\mathrm{k}\mathrm{g}$