For the combustion of n-octane C 8 H 18 + O 2 → C O 2 + H 2 O at 25 o C i g n o r e r e s o n a n c e i n C O 2

n-Octane existed as liquid from, C 8 H 1 8 - l + 2 5 2 O 2 → 8 CO 2 g + 9 H 2 O l Δ n g = 8 - 12.5 = - 4.5 Δ H = Δ E + Δ n g RT Δ H = Δ E - 4.5 × 8.31 × 0.298 in kJ/mol

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ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

For the combustion of n-octane $C_{8} H_{18} + O_{2} \to C O_{2} + H_{2} O$ at $25^{o} C (i g n o r e r e s o n a n c e i n C O_{2})$

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Solution:

n-Octane existed as liquid from, $C_{8} H_{18 - (l)} + \frac{25}{2} O_{2} \to 8 {CO}_{2 (g)} + 9 H_{2} O_{(l)}$

$Δ n_{g} = 8 - 12.5 = - 4.5$
$Δ H = Δ E + Δ n_{g} RT$
$Δ H = Δ E - 4.5 \times 8.31 \times 0.298 in kJ/mol$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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