Start Free Mock LoginAlready registered? Login here

Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2011

ChemistryEasysingle choice

For the reaction, $C_{3} H_{8} (g) + 5 O_{2} (g) ⟶ 3 CO_{2} (g) + 4 H_{2} O (l)$ at constant temperature, $Δ H - Δ E$ is

Options:

Answer:

Solution:

$C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 CO_{2} (g) + 4 H_{2} O (l) Δ n_{g} = n_{p} - n_{r} = 3 - 6 = - 3 Δ H = Δ E + Δ n_{g} RT Δ H = Δ E - 3 RT Δ H - Δ E = - 3 RT$

Stream:VITEEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2011

Doubts & Discussion

Loading discussions...