The difference between heat of reaction and change in internal energy at constant volume for the reaction given below at 25^oC in kJ is

$2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 {CO}_{2} (g) + 6 H_{2} O (l)$

Question

The difference between heat of reaction and change in internal energy at constant volume for the reaction given below at 25 o C in kJ is 2 C 6 H 6 l + 15 O 2 g → 12 CO 2 g + 6 H 2 O l

TestHub · Accepted Answer

Δ H ⁡ = Δ E ⁡ + Δ n g RT Δ H ⁡ - Δ E ⁡ = Δ n g RT = 1 2 - 1 5 × 8. 3 1 4 × 2 9 8 = - 7. 4 3 2 k J

Chemistry - Thermochemistry Question with Solution | TestHub

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