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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

The difference between heats of reaction at constant pressure and constant volume for the reaction,
$2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 C O_{2} (g) + 6 H_{2} O (l)$ at $25 ° C$ in kJ is

Options:

Answer:

Solution:

$Δ H - Δ E = Δ n_{g} R T$
$Δ n_{g} = 12 - 15 = - 3$
So $ΔH - ΔE = - 3 × 8 .314 J {mol}^{- 1} K^{- 1} × 298 K$
$= - 7.43 kJ {mol}^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

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