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ChemistryThermochemistryHess's Law of Constant Heat SummationMedium2 minQB

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Passage / Comprehension

When 1 gm equivalent of strong acid reacts with strong base heat released is 57.3 kJ, when 1 gm equivalentof H₂A is completely reacts with strong base 56.1 kJ heat is released. When 1 gm equivalent of B(OH)₂ is completely reacts with strong acid 48.8 kJ heat is released.

The enthalpy of ionisation of $B (OH)_{2}$ is

Options:

Answer:

Solution:

$Δ H_{neut} (H_{2} A +$ strong base $) = Δ H_{ion} (H_{2} A) + Δ H_{neut}$ (strong acid + strong base)

$- 48.8 = Δ H_{ion} (H_{2} A) - 57.3$

$Δ H_{i o n} (H_{2} A) = 8.5 kJ / e q u i v a l e n t = 17 kJ / mole$

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Hess's Law of Constant Heat Summation

⏱ 2mℹ️ Source: QB

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