Start Free Mock LoginAlready registered? Login here

Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

The difference between heats of reaction at constant pressure and constant volume for the reaction,
$2 C_{6} H_{6} (l) + 15 O_{2} (g) \to 12 C O_{2} (g) + 6 H_{2} O (l)$ at $25 ° C$ in kJ is

Options:

Answer:

Solution:

${Δn}_{g} = 12 - 15 = - 3$
$ΔH = ΔE + {Δn}_{g} RT$
or $ΔH - ΔE = {Δn}_{g} RT$
$= - 3 \times 8.314 {Jmol}^{- 1} K^{- 1} \times 298 K$
$= - 7.43 k J m o l^{- 1}$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...