Standard enthalpy of vaporisation Δ vap H s for water at 10 0 ∘ C is 40.66 kJ mol − 1 . The internal energy of vaporisation of water at 10 0 ∘ C (in kJ mol − 1 ) is (Assume water vapour to behave li

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Standard enthalpy of vaporisation Δ vap ​ H s for water at 10 0 ∘ C is 40.66 kJ mol − 1 . The internal energy of vaporisation of water at 10 0 ∘ C (in kJ mol − 1 ) is (Assume water vapour to behave like an ideal gas).NEET 2012 (Screening)

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H 2 ​ O ( l ) ⟶ 10 0 ∘ C ​ H 2 ​ O ( g ) Δ vap ​ H s = Δ vap ​ E s + Δ n g ​ RT For the above reaction, Δ n g ​ = n p ​ − n r ​ = 1 − 0 = 1 ∴ 40.66 kJ mol − 1 = Δ vap ​ E s + 1 × 8.314 × 1 0 − 3 × 373 Δ vap ​ E s = 40.66 kJ mol − 1 − 3.1 kJ mol − 1 = + 37.56 kJ mol − 1 ​

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