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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionMedium2 minPYQ_2008

ChemistryMediumsingle choice

Bond dissociation enthalpy of $H_{2}, Cl_{2}$ and $HCl$ are 434,242 and $431 kJmol^{-}$ $^{1}$ respectively. Enthalpy of formation of $HCl$ isNEET 2008 (Mains)

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$2 [H] + 2 [Cl] ⟶ 2 HCl, Δ H = - 862 kJ mol^{- 1} H_{2} ⟶ 2 [H], Δ H = 434 kJ Cl_{2} ⟶ 2 [Cl], Δ H = 242 kJ H_{2} + Cl_{2} ⟶ 2 HCl, Δ H = - 186 kJ ∴ Δ H_{4} of HCl = \frac{- 186}{2} = - 93 kJ mol^{- 1}$

Stream:NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2008

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