Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020
ChemistryEasysingle choice

The enthalpies of combustion of carbon and carbon monoxide are-393.5and-283 kJmol-1respectively. The enthalpy of formation of carbon monoxide per mole is

Options:

Answer:
B
Solution:

(i)C(s)+O2(g)→CO2(g)ΔH=-393.5 kJ
(ii)CO(g)+12O2(g)→CO2(g)ΔH=-283.0 kJ
eq. (i) and (ii) gives
(iii)C(s)+12O2(g)→CO(g)ΔH=-110.5 kJ
This equation (iii) also represents formation of one mole of CO and thus enthalpy change is the heat of formation of CO (g).

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction
⏱ 2mℹ️ Source: PYQ_2020

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