Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryHess's Law of Constant Heat SummationMedium2 minQB

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Passage / Comprehension

When 1 gm equivalent of strong acid reacts with strong base heat released is 57.3 kJ, when 1 gm equivalentof H₂A is completely reacts with strong base 56.1 kJ heat is released. When 1 gm equivalent of B(OH)₂ is completely reacts with strong acid 48.8 kJ heat is released.

The heat released when 1 mole of $H_{2} A$ is completely neutralised by $B (OH)_{2}$ is :

Options:

Answer:

Solution:

$Δ H_{neut} (H_{2} A + B (OH)_{2}) = Δ H_{ion} (H_{2} A) + Δ H_{ion} B (OH)_{2} + Δ H_{neut}$ (strong acid + strong base)

$= (1.2 + 8.5 - 57.3) \times 2 = 95.2 kJ$

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Hess's Law of Constant Heat Summation

⏱ 2mℹ️ Source: QB

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