Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of CombustionMedium2 minQB
ChemistryMediumnumerical
The heat evolved on combustion of 1 g of sucrose, C12H22O11, into CO2(g) and H2O(l) is 3.5 kcal. Heat of formation of CO2(g) and H2O(l) are -94.2 and -68.4 kcal/mol, respectively. The magnitude of standard enthalpy of formation of 1 g of sucrose (in kcal) is
Answer:
2.00
Solution:
C12H22O11 + 12O2 → 12CO2 + 11H2O(l); per mole (342 g), ΔHcomb = 342 × (-3.5) = -1197 kcal. Δf H(sucrose) = 12(-94.2) + 11(-68.4) - (-1197) = -1130.4 - 752.4 + 1197 = -685.8 kcal/mol = -685.8/342 ≈ -2.0 kcal/g. Magnitude = 2 kcal.
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB
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