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Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2017

ChemistryEasysingle choice

Consider the reaction : $N_{2} + 3 H_{2} \to 2 NH_{3}$ carried out at constant temperature and pressure. If $Δ H$ and $Δ U$ are the enthalpy and internal energy changes for the reaction, which of the following expressions is true?

Options:

Answer:

Solution:

$Δ H = Δ U + Δ nRT$ for $N_{2} + 3 H_{2} ⟶ 2 NH_{3} Δ n_{g} = 2 - 4 = - 2$ $∴ Δ H = Δ U - 2 RT$ or $Δ U = Δ H + 2 RT ∴ Δ U > Δ H$

Stream:VITEEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2017

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