The enthalpy change for the reaction, NaOH(aq) + HCl(aq) → NaCl(aq) + H 2 O(l) is -57 kJ. Predict the value of the enthalpy change in the following reaction: Ba(OH) 2 (aq) + H 2 SO 4 (aq) → BaSO 4 (s) + 2H 2 O(l)

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ChemistryThermochemistryEnthalpy of NeutralisationEasy2 minQB

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The enthalpy change for the reaction, NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l) is -57 kJ. Predict the value of the enthalpy change in the following reaction:

Ba(OH)₂(aq) + H₂SO₄(aq) → BaSO₄(s) + 2H₂O(l)

Options:

Answer:

Solution:

Two moles of water are formed, contributing 2 × (-57) = -114 kJ. In addition, BaSO_₄ precipitates. The enthalpy of precipitation for Ba^²⁺ and SO_₄^²⁻ is exothermic, meaning the total enthalpy change must be more negative than -114 kJ. The only option that fits this condition is -200 kJ, which is option (d).

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Neutralisation

⏱ 2mℹ️ Source: QB

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