20 ml mixture of C 3 H 8 and CO gas when burnt in excess of oxygen produce 40 ml CO 2 gas. Choose the correct statement(s). (Volume of gases measured under same T & P)

Question

20 ml mixture of C 3 ​ H 8 ​ and CO gas when burnt in excess of oxygen produce 40 ml CO 2 ​ gas. Choose the correct statement(s). (Volume of gases measured under same T & P)

TestHub · Accepted Answer

Question Explanation:

Analyzing the combustion of a propane and CO mixture.

Concept:

Stoichiometry of Gaseous Reactions.

Solution:

Write balanced combustion equations for propane (C₃H₈) and carbon monoxide (CO). Use the total volume of CO₂ produced to set up an equation and find the initial volumes of the reactants. Then, calculate the oxygen used and the total volume contraction.

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

V 5V 3V

CO + $\frac{1}{2}$ O₂ → CO₂

20 – V $\frac{1}{2}$ (20 – V) 20 – V

$V_{C O_{2}} = 40$

$3 V + (20 - V) = 40 \Rightarrow V = 10 m L$

$V_{C O} = 10 = V_{C_{3} H_{8}}$

$V_{C o n t .} = V_{ini t ia l} - V_{f ina l}$ =

$3 V + \frac{( 20 - V )}{2} = 3 \times 10 + \frac{10}{2} = 35 m l$

$V_{o_{2}} = 5 V + \frac{20 - V}{2} = 5 \times 10 + \frac{10}{2} = 55 m l$

Statements 2 and 3 are correct.

Final Answer: option (B) & (C)

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Options:(select one or more)

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