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ChemistryStoichiometryProblems Based on Mixtures, Percentage PurityMedium2 minQB

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The vapour density of a mixture containing CO and $CO_{2}$ is 18 . The mole fraction of CO in the mixture is:

Answer:

Solution:

$M_{W} = 2 \times VD = 2 \times 18 = 36$

$36 = \frac{44 \times n _{1} + 28 n _{2}}{n _{1} + n _{2}} n_{1} = n_{2}$

Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Problems Based on Mixtures, Percentage Purity

⏱ 2mℹ️ Source: QB

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