An element (metal) crystallizes in fcc lattice having edge length 400 pm . Calculate the maximum diameter of atom which can be placed in interstitial site without distorting the structure in pm. ( 2

Question

An element (metal) crystallizes in fcc lattice having edge length 400 pm . Calculate the maximum diameter of atom which can be placed in interstitial site without distorting the structure in pm. ( 2 ​ = 1.414 )

TestHub · Accepted Answer

a = 400 pm

There are two types of void in fcc. The size of O.V. > T.V.

$\frac{r _{O . V .}}{r _{a t o m}} = 0.414$

Therefore, $r_{O . V .} = 0.414 r_{a t o m}$ .

$r_{O . V .} d_{O . V .} d_{O . V .} = 0.414 (\frac{a}{2 2}) = 0.414 (\frac{a}{2}) = \frac{0.414 ( 2 )}{2} \times 400 = 117.0792 p m$

Chemistry - Solid State Question with Solution | TestHub

Doubts & Discussion