Chemistry - Solid State Question with Solution | TestHub

Molecular weight of$\text{CuCl}=63.5+35.5=99$
For face centred cubic cell
$\text{z}\text{=}\text{4}$
$\text{Density}\text{=}\frac{\text{z}\text{×}\text{molecular}\text{weight}}{{\text{a}}^{\text{3}}\text{×}{\text{N}}_{\text{A}}}$
$3.4=\frac{4\times 99}{{\mathrm{a}}^3\times 6.023\times 10^{23}}$
$\text{a}=5.783\times {10}^{-8}\text{cm}$
$\text{=}\text{5}\text{.783}\text{Å}$.