A metal crystalizes in a BCC lattice with edge of unit cell 10 3 A ˚ . Then distance in A ˚ between two nearest neighbours is?

2 3 a = 2 3 × 3 A ˚ = 1.50 A ˚

Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minQB

ChemistryMediuminteger

A metal crystalizes in a BCC lattice with edge of unit cell $103 \overset{˚}{A}$ . Then distance in $\overset{˚}{A}$ between two nearest neighbours is?

Answer:

Solution:

$\frac{3 a}{2} = \frac{3 \times 3 A ˚}{2} = 1.50 \overset{˚}{A}$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: QB

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