Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StatePacking in lonic SolidsMedium2 minQB

ChemistryMediumsingle choice

The packing fraction in the CsCl structure with anion-anion contact along with anion -cation contact will be -

Answer:

Solution:

In a CsCl structure:

Anion–anion contact gives the edge length:

$a = 2 r_{-}$

Along the body diagonal, the anion and cation touch:

$3 a = 2 (r_{+} + r_{-})$

Therefore:

$\frac{r _{+}}{r _{-}} = 3 - 1$

Packing fraction:

$PF = \frac{\frac{4}{3} π ( r _{-}^{3} + r _{+}^{3} )}{a ^{3}} = \frac{π}{6} [1 + (3 - 1)^{3}]$

Answer: $\frac{π}{6} [1 + (3 - 1)^{3}]$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Packing in lonic Solids

⏱ 2mℹ️ Source: QB

Loading discussions...