Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

The number of atoms in 100 g of an fcc crystal with density=10.0 gcm-3and cell edge equal to 200 pm is equal to

Options:

Answer:
A
Solution:

ρ=Zeff×Mwa3×10-30×NA
[For fcc,Zeff=4/unit cell]
So,Mw=ρ×a3×10-30×NAZeff
10.0 g  cm −3  ×  (200) 3  ×  10 −30 cm 3  × 6.02 ×  10 23 4
=12 g
As 12 g has number of atoms =6.02×1023
So, 100 g has number of atoms =6.02×1023×10012=5×1024

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Solid StateSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2020

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