Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minQB

ChemistryMediumsingle choice

In diamond, carbon atom occupy FCC lattice points as well as alternate tetrahedral voids. If edge length of the unit cell is 356 pm , then radius of carbon atom is

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Answer:

Solution:

In diamond, atoms touch along the body diagonal, so

$2 r = \frac{3}{4} a \Rightarrow r = \frac{3}{8} a$ .

Given $a = 356 p m$ ,

$r = \frac{3}{8} \times 356 = \frac{1.732 \times 356}{8} \approx 77 p m$ .

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: QB

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