Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

In diamond structure, carbon atoms form fcc lattice and 50% of tetrahedral voids occupied by carbon atoms. Every carbon atom is surrounded tetrahedrally by four carbon atoms with bond length 173.2 pm. On the basis

of above information answer following questions (N_A = 6 × 10²³ )

The density of diamond unit cell is (in $gm / cm^{3}$ )

Options:

Answer:

Solution:

$\frac{3 a}{4} = 173.2 \Rightarrow a = 400$

$d = \frac{8 \times 12}{6 \times 1 0 ^{23} \times ( 4 \times 1 0 ^{- 8} ) ^{3}} = \frac{96}{38.4} = 2.5$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: QB

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