In a normal spinel types structure, the oxide ions are arranged in c c p whereas 1 / 8 tetrahedral holes are occupied by Z n 2 + i o n s and 50 % of octahedral holes are occupied by F e 3 + i o n s .

Question

In a normal spinel types structure, the oxide ions are arranged in c c p whereas 1 / 8 tetrahedral holes are occupied by Z n 2 + i o n s and 50 % of octahedral holes are occupied by F e 3 + i o n s . The formula of the compound is -

TestHub · Accepted Answer

In one unit cell no. of O 2 + = 4 The no. of Z n 2 + = 1 8 × 8 = 1 The no. of F e 3 + = 1 2 × 4 = 2 ∴ molecular formula of given spinel structure is Z n F e 2 O 4

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