Chemistry - Solid State Question with Solution | TestHub

Volume of the metal $V=\frac{\text{Mass}}{\text{Density}}=\frac{0.6}{8.5}$ cm${}^3$

Number of unit cells $=\frac{V}{\text{Volume of one unit cell}}=\frac{0.6}{8.5\times 3.6\times 10^{-23}}$

Since the metal forms a bcc structure, the number of atoms per unit cell is $Z=2$.

Total number of atoms $=2\times \frac{0.6}{8.5\times 3.6\times 10^{-23}}$

$=\frac{1.2}{30.6\times 10^{-23}}$

$=0.0392\times 10^{23}=3.92\times 10^{21}$

Answer: $3.92\times 10^{21}$