Chemistry - Solid State Question with Solution | TestHub

We have:

Theoretical density = $\frac{zM}{NV}=\frac{zM}{N_{}{a}^3}$

For a b.c.c. lattice, $z=2$. Given that

$a=3.50\times 10^{-10}m$ and $M=7\times 10^{-3}kg/mole$.

$$d_{cal}=\frac{2\times \left(7\times 10^{-3}\right)kg/mole}{6.022\times 10^{23}mol{e}^{-1}\times (3.50\times 10^{-10}m{)}^3}$$

$$d_{cal}=5.42\times 10^{2}kg{m}^{-3}$$

Percentage occupancy = $\frac{5.30\times 10^{2}kg{m}^{-3}}{5.42\times 10^{2}kg{m}^{-3}}\times 100=97.78\%$